Question

qse 1 retest 25-26
newtons second law of motion is expressed as f = ma, if a net force of 10n is applied to an object with a mass of 2 kg, what is the objects acceleration?
10 m/s²
5 m/s²
20 m/s²
2 m/s²

Explanation:

Step1: Rearrange the formula

Given $F = ma$, we can solve for $a$ by dividing both sides by $m$, so $a=\frac{F}{m}$.

Step2: Substitute values

We know $F = 10N$ and $m = 2kg$. Substitute into the formula: $a=\frac{10N}{2kg}$.

Step3: Calculate

$a = 5m/s^{2}$.

Answer:

$5m/s^{2}$