Question

this punnett square shows a cross between two holsteins. what is the probability that a holstein produced by this cross will have red - to - black spots? % submit

Explanation:

Step1: Count the total number of offspring

There are 4 boxes in the Punnett square, so the total number of possible offspring is \(n = 4\).

Step2: Count the number of offspring with red - to - black spots

The genotype for red - to - black spots is \(m^{r}m^{r}\). There is 1 box with the genotype \(m^{r}m^{r}\), so the number of favorable outcomes \(k=1\).

Step3: Calculate the probability

The probability \(P=\frac{k}{n}\). Substituting \(k = 1\) and \(n = 4\), we get \(P=\frac{1}{4}=0.25\). To convert to a percentage, we use the formula \(P(\%)=P\times100\). So \(P(\%)=0.25\times 100 = 25\%\).

Answer:

25