Question

a projectile is launched horizontally at a speed of 40 meters per second from a platform located a vertical distance h above the ground. the projectile strikes the ground after time t at horizontal d from the base of the platform. if we ignore air resistance, meters is the horizontal distance or range if the projectiles time of flight is 2.5 seconds.

Explanation:

Step1: Ecuación de movimiento horizontal

En movimiento horizontal sin aceleración (ignorando resistencia del aire), la distancia horizontal \(d\) se calcula con la fórmula \(d = v\times t\), donde \(v\) es la velocidad horizontal y \(t\) es el tiempo.

Step2: Sustituir valores

Dado \(v = 40\space m/s\) y \(t = 2.5\space s\), sustituimos en la fórmula: \(d=40\times2.5\).

Step3: Cálculo final

Realizando la multiplicación \(40\times2.5 = 100\space m\).

Answer:

100