Question

programming with relational operators
int a = 2;
int b = 3;
int c = 6;
if (a * b >= c)
system.out.println(\totally\);
if (a + 2 * b != c)
system.out.println(\awesome\);
what is the output of the program?
totally awesome
avesome
no output is generated.

Explanation:

Step1: Evaluate the first if condition

Calculate \(a * b\), where \(a = 2\) and \(b = 3\). So \(a*b=2*3 = 6\). The condition is \(a * b>=c\) (since \(c = 6\)), \(6>=6\) is \(true\). So "totally" is printed.

Step2: Evaluate the second if condition

Calculate \(a + 2*b\), where \(a = 2\) and \(b = 3\). Using order of operations (multiplication first), \(2*b=6\), then \(a + 2*b=2 + 6=8\). The condition is \(a + 2*b!=c\) (since \(c = 6\)), \(8!=6\) is \(true\). So "awesome" is printed.

Answer:

totally awesome