Question

a process generates 250 watts of useful energy, and it has an input of 850 watts, which includes 600 watts of waste energy along with the 250 watts of useful energy. what is the efficiency of the process? (1 point) 71% 42% 2.4% 29%

Explanation:

Step1: Recall the efficiency formula

Efficiency ($\eta$) is given by the formula $\eta=\frac{\text{Useful energy output}}{\text{Total energy input}}\times100\%$.

Step2: Substitute the given values

Here, useful energy output $= 250$ watts and total energy input $= 850$ watts.
So, $\eta=\frac{250}{850}\times100\%$.

Step3: Calculate the value

$\frac{250}{850}\times100\%=\frac{25000}{850}\% \approx 29.41\% \approx 29\%$ (rounded to the nearest whole number).

Answer:

29%