Question

problem 6: two siblings are playing with the seesaw. one of the kids sits at a distance of 1.3 m from the center and has a mass of 30 kg. what torque is the child exerting on the seesaw with respect to the center of the seesaw?

Explanation:

Step1: Calculate the force exerted by the child

The force \(F\) exerted by the child is due to gravity, \(F = mg\), where \(m = 30\space kg\) and \(g=9.8\space m/s^{2}\).
\(F=30\times9.8 = 294\space N\)

Step2: Calculate the torque

The formula for torque \(\tau\) is \(\tau=rF\sin\theta\). Assuming the child is sitting perpendicular to the seesaw (\(\theta = 90^{\circ}\), \(\sin\theta = 1\)), and \(r = 1.3\space m\).
\(\tau=1.3\times294\)
\(\tau = 382.2\space N\cdot m\)

Answer:

\(382.2\space N\cdot m\)