Question

problem 1 redo
solve.
$3x+\frac{2}{3}=\frac{29}{3}$
$x = \square$
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previous problem

Explanation:

Step1: Subtract $\frac{2}{3}$ from both sides

$3x + \frac{2}{3} - \frac{2}{3} = \frac{29}{3} - \frac{2}{3}$
$3x = \frac{27}{3}$

Step2: Simplify the right side and divide by 3

$3x = 9$
$\frac{3x}{3} = \frac{9}{3}$
$x = 3$

Answer:

$3$