Question

problem 20:
(first taught in lesson 24)
find x and y.
after you enter your answer press go.
x = y =

Explanation:

Step1: Recall the sum of interior angles of a quadrilateral

The sum of interior angles of a quadrilateral is \(360^{\circ}\).

Step2: Set up the equation

We have \(90^{\circ}+6x^{\circ}+4y^{\circ}+5y^{\circ}=360^{\circ}\). Also, since the two sides with arrows are parallel, we know that \(5y + 4y=180\) (same - side interior angles).

For \(y\):

\(5y + 4y=180\)
\(9y=180\)
\(y = 20\)

For \(x\):

Substitute \(y = 20\) into \(90+6x + 4y+5y=360\).
\(90+6x+9y=360\)
\(90+6x+9\times20=360\)
\(90+6x + 180=360\)
\(6x+270=360\)
\(6x=360 - 270\)
\(6x=90\)
\(x = 15\)

Answer:

\(x = 15\), \(y = 20\)