Question

problem 10: (first taught in lesson 45) the lengths of two sides of a triangle are 45 and 65. find the lengths that the third side must be greater than and less than. after you enter your answer press go. greater than and less than

Explanation:

Step1: Apply triangle side - length rule

The length of the third side \(x\) of a triangle with two sides \(a = 45\) and \(b=65\) satisfies \(|a - b|\lt x\lt a + b\).

Step2: Calculate \(|a - b|\)

\(|45-65|=| - 20|=20\).

Step3: Calculate \(a + b\)

\(45 + 65=110\).

Answer:

Greater than \(20\) and less than \(110\)