Question

practice test
the graph shows the momentum y, in newton - seconds, of an object x
seconds after the object started moving, for ( 0 leq x leq 8 ). what is the average
rate of change, in newton - seconds per second, in the momentum of the
object from ( x = 2 ) to ( x = 6 )?
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Explanation:

Step1: Find the values of \(y\) at \(x = 2\) and \(x = 6\)

From the graph, when \(x = 2\), \(y=4\). When \(x = 6\), \(y = 4\).

Step2: Use the average - rate - of - change formula

The average rate of change formula is \(\frac{\Delta y}{\Delta x}=\frac{y_2 - y_1}{x_2 - x_1}\). Here, \(x_1 = 2,y_1 = 4,x_2=6,y_2 = 4\). Then \(\frac{y_2 - y_1}{x_2 - x_1}=\frac{4 - 4}{6 - 2}\).

Step3: Calculate the result

\(\frac{4 - 4}{6 - 2}=\frac{0}{4}=0\)

Answer:

\(0\)