5. - / 6 points

perform the following temperature conversions.
a.) 240 °c = k
b.) 398 k = °c
c.) 240 °c = °f
d.) 404 °f = °c
e.) -432 °f = k
f.) 972 k = °f

Question

5. - / 6 points

perform the following temperature conversions.
 a.) 240 °c = k
 b.) 398 k = °c
 c.) 240 °c = °f
 d.) 404 °f = °c
 e.) -432 °f = k
 f.) 972 k = °f

Accepted Answer

### Part a: $ 240^\circ \text{C} $ to $ \text{K} $
# Explanation:
## Step1: Recall the formula $ K = ^\circ\text{C} + 273.15 $
$ K = 240 + 273.15 $
## Step2: Calculate the sum
$ K = 513.15 $
# Answer:
$ 513.15 $

### Part b: $ 398 \text{K} $ to $ ^\circ\text{C} $
# Explanation:
## Step1: Recall the formula $ ^\circ\text{C} = K - 273.15 $
$ ^\circ\text{C} = 398 - 273.15 $
## Step2: Calculate the difference
$ ^\circ\text{C} = 124.85 $
# Answer:
$ 124.85 $

### Part c: $ 240^\circ \text{C} $ to $ ^\circ\text{F} $
# Explanation:
## Step1: Recall the formula $ ^\circ\text{F} = \frac{9}{5}^\circ\text{C} + 32 $
$ ^\circ\text{F} = \frac{9}{5} \times 240 + 32 $
## Step2: Calculate $ \frac{9}{5} \times 240 $
$ \frac{9}{5} \times 240 = 432 $
## Step3: Add 32
$ ^\circ\text{F} = 432 + 32 = 464 $
# Answer:
$ 464 $

### Part d: $ 404^\circ \text{F} $ to $ ^\circ\text{C} $
# Explanation:
## Step1: Recall the formula $ ^\circ\text{C} = \frac{5}{9}(^\circ\text{F} - 32) $
$ ^\circ\text{C} = \frac{5}{9}(404 - 32) $
## Step2: Calculate $ 404 - 32 $
$ 404 - 32 = 372 $
## Step3: Multiply by $ \frac{5}{9} $
$ ^\circ\text{C} = \frac{5}{9} \times 372 \approx 206.67 $
# Answer:
$ 206.67 $

### Part e: $ -432^\circ \text{F} $ to $ \text{K} $
# Explanation:
## Step1: Convert $ ^\circ\text{F} $ to $ ^\circ\text{C} $ using $ ^\circ\text{C} = \frac{5}{9}(^\circ\text{F} - 32) $
$ ^\circ\text{C} = \frac{5}{9}(-432 - 32) = \frac{5}{9}(-464) \approx -257.78 $
## Step2: Convert $ ^\circ\text{C} $ to $ \text{K} $ using $ K = ^\circ\text{C} + 273.15 $
$ K = -257.78 + 273.15 = 15.37 $
# Answer:
$ 15.37 $

### Part f: $ 972 \text{K} $ to $ ^\circ\text{F} $
# Explanation:
## Step1: Convert $ \text{K} $ to $ ^\circ\text{C} $ using $ ^\circ\text{C} = K - 273.15 $
$ ^\circ\text{C} = 972 - 273.15 = 698.85 $
## Step2: Convert $ ^\circ\text{C} $ to $ ^\circ\text{F} $ using $ ^\circ\text{F} = \frac{9}{5}^\circ\text{C} + 32 $
$ ^\circ\text{F} = \frac{9}{5} \times 698.85 + 32 $
## Step3: Calculate $ \frac{9}{5} \times 698.85 $
$ \frac{9}{5} \times 698.85 = 1257.93 $
## Step4: Add 32
$ ^\circ\text{F} = 1257.93 + 32 = 1289.93 $
# Answer:
$ 1289.93 $

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QUESTION IMAGE

Question

Explanation:

Part a: \( 240^\circ \text{C} \) to \( \text{K} \)

Step1: Recall the formula \( K = ^\circ\text{C} + 273.15 \)

Step2: Calculate the sum

Step1: Recall the formula \( ^\circ\text{C} = K - 273.15 \)

Step2: Calculate the difference

Step1: Recall the formula \( ^\circ\text{F} = \frac{9}{5}^\circ\text{C} + 32 \)

Step2: Calculate \( \frac{9}{5} \times 240 \)

Step3: Add 32

Answer:

Part b: \( 398 \text{K} \) to \( ^\circ\text{C} \)