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Question
point-slope form practice
write the slope-intercept form of th
- $y + 1 = \frac{5}{3}(x + 3)$
- $y + 4 = -9(x - 1)$
Step1: Expand the right-hand side
- $y + 1 = \frac{5}{3}x + \frac{15}{3}$
- $y + 4 = -9x + 9$
Step2: Simplify constants
- $y + 1 = \frac{5}{3}x + 5$
- $y + 4 = -9x + 9$
Step3: Isolate y
- $y = \frac{5}{3}x + 5 - 1$
- $y = -9x + 9 - 4$
Step4: Calculate final constants
- $y = \frac{5}{3}x + 4$
- $y = -9x + 5$
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- $y = \frac{5}{3}x + 4$
- $y = -9x + 5$