Question

the point j(-2, 6) is reflected over the x-axis. what are the coordinates of the resulting point, j?

Explanation:

Step1: Recall reflection over x - axis rule

When a point \((x,y)\) is reflected over the \(x\) - axis, the \(x\) - coordinate remains the same and the \(y\) - coordinate changes its sign. The formula for the reflection of a point \((x,y)\) over the \(x\) - axis is \((x,y)\to(x, - y)\).

Step2: Apply the rule to point \(J(-2,6)\)

For the point \(J(-2,6)\), the \(x\) - coordinate is \(-2\) and the \(y\) - coordinate is \(6\). Using the reflection rule over the \(x\) - axis, we keep the \(x\) - coordinate the same (\(x=-2\)) and change the sign of the \(y\) - coordinate. So the new \(y\) - coordinate is \(-6\).

Answer:

The coordinates of the resulting point \(J'\) are \((-2,-6)\)