Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

plot five parabolas. each parabola should pass through the origin and a…

Question

plot five parabolas. each parabola should pass through the origin and a pair of color - coordinated points. one is done for you. when you finish, press \check my work\.

Explanation:

Step1: Determine the general form of a parabola

The general form of a parabola is \(y = ax^{2}+bx + c\). Since it passes through the origin \((0,0)\), substituting \(x = 0\) and \(y=0\) gives \(c = 0\). So the equation simplifies to \(y=ax^{2}+bx\). For a parabola symmetric about the \(y -\)axis (since the given red parabola is symmetric about the \(y -\)axis and we assume the other parabolas based on the symmetric - point pairs), \(b = 0\), and the equation is \(y = ax^{2}\).

Step2: For the blue - colored points

Let the blue - colored points be \((- 4,y_1)\) and \((4,y_1)\). Substituting \(x=-4\) and \(y = y_1\) (say \(y_1 = 3\)) into \(y = ax^{2}\), we get \(3=a\times(-4)^{2}\), so \(a=\frac{3}{16}\). The equation of the parabola passing through the blue - colored points is \(y=\frac{3}{16}x^{2}\).

Step3: For the purple - colored points

Let the purple - colored points be \((-3,y_2)\) and \((3,y_2)\) (assuming \(y_2=-2\)). Substituting \(x = 3\) and \(y=-2\) into \(y=ax^{2}\), we have \(-2=a\times3^{2}\), so \(a=-\frac{2}{9}\). The equation of the parabola passing through the purple - colored points is \(y =-\frac{2}{9}x^{2}\).

Step4: For the orange - colored points

Let the orange - colored points be \((-1,y_3)\) and \((1,y_3)\) (assuming \(y_3=-1\)). Substituting \(x = 1\) and \(y=-1\) into \(y=ax^{2}\), we get \(-1=a\times1^{2}\), so \(a=-1\). The equation of the parabola passing through the orange - colored points is \(y=-x^{2}\).

Step5: For the green - colored points

Let the green - colored points be \((-3,y_4)\) and \((3,y_4)\) (assuming \(y_4=-4\)). Substituting \(x = 3\) and \(y=-4\) into \(y=ax^{2}\), we have \(-4=a\times3^{2}\), so \(a=-\frac{4}{9}\). The equation of the parabola passing through the green - colored points is \(y =-\frac{4}{9}x^{2}\).

Answer:

Use the equations \(y=\frac{3}{16}x^{2}\) (for blue points), \(y =-\frac{2}{9}x^{2}\) (for purple points), \(y=-x^{2}\) (for orange points), \(y =-\frac{4}{9}x^{2}\) (for green points) to plot the remaining four parabolas on the coordinate - plane.