Question

a plant heterozygous for yellow seeds is crossed with a plant homozygous for green seeds. use the punnett square to predict the phenotype of the offspring. 1 yellow 2 green 3 yellow 4

Explanation:

Step1: Determine Genotypes

The heterozygous yellow - seeded plant has genotype \( Yy \) (since yellow is dominant, let \( Y \) represent yellow allele and \( y \) represent green allele), and the homozygous green - seeded plant has genotype \( yy \).

Step2: Fill Punnett Square

• For cell 1: The top allele is \( Y \) and the side allele is \( y \), so the genotype is \( Yy \). The phenotype for \( Yy \) (yellow is dominant) is yellow.
• For cell 2: The top allele is \( y \) and the side allele is \( y \), so the genotype is \( yy \). The phenotype for \( yy \) is green.
• For cell 3: The top allele is \( Y \) and the side allele is \( y \), so the genotype is \( Yy \). The phenotype for \( Yy \) is yellow.
• For cell 4: The top allele is \( y \) and the side allele is \( y \), so the genotype is \( yy \). The phenotype for \( yy \) is green.

Answer:

1. green