Question

planet distance (astronomical units) planet distance (astronomical units) neptune 30.06 mars 1.52 mercury 0.39 saturn 9.539 jupiter 5.203 earth 1 part: 0 / 2 part 1 of 2 (a) find the mean and median distance from the sun. round to 2 decimal places where necessary. the mean distance from the sun is and the median distance from the sun is

Explanation:

Step1: Calculate the sum of distances

$0.39 + 5.203+30.06 + 1.52+9.539 + 1=47.712$

Step2: Calculate the mean

The number of data - points $n = 6$. Mean $\bar{x}=\frac{47.712}{6}=7.952\approx7.95$

Step3: Arrange the data in ascending order

$0.39,1,1.52,5.203,9.539,30.06$

Step4: Calculate the median

Since $n = 6$ (an even number), the median is the average of the $\frac{n}{2}$th and $(\frac{n}{2}+1)$th ordered data - points. $\frac{n}{2}=3$ and $\frac{n}{2}+1 = 4$. Median $=\frac{1.52 + 5.203}{2}=\frac{6.723}{2}=3.3615\approx3.36$

Answer:

The mean distance from the sun is $7.95$ and the median distance from the sun is $3.36$