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in the photoelectric effect, if the intensity of light shone on a metal…

Question

in the photoelectric effect, if the intensity of light shone on a metal increases, what will happen? answer: a ejected electrons will be faster. b ejected electrons will be slower. c there will be more electrons ejected. d there will be fewer electrons ejected. e no change is observed.

Explanation:

Brief Explanations

In the photoelectric effect, the intensity of light is related to the number of photons. When the intensity increases, there are more photons hitting the metal surface. Each photon can eject one electron (if its energy is above the work - function). So, more photons mean more electrons are ejected. The speed of the ejected electrons (kinetic energy) is determined by the frequency of the light (from the equation \(E = h
u-\Phi\), where \(E\) is the kinetic energy of the electron, \(h\) is Planck's constant, \(
u\) is the frequency of light, and \(\Phi\) is the work - function of the metal). Since the problem only mentions an increase in intensity (not frequency), the speed of electrons does not change.

Answer:

C. There will be more electrons ejected.