Question

the perimeter of square jklm is 48 units. what is the value of x? 6 9 12 15

Explanation:

Step1: Recall the formula for the perimeter of a square

The perimeter \(P\) of a square is given by \(P = 4s\), where \(s\) is the side - length of the square.

Step2: Find the side - length of the square

Given \(P=48\) units. Using \(P = 4s\), we can solve for \(s\):

$$s=\frac{P}{4}$$

Substitute \(P = 48\) into the formula:

$$s=\frac{48}{4}=12$$

Step3: Set up an equation for \(x\)

Since the side - length \(s=x + 3\) and \(s = 12\), we have the equation \(x+3=12\).

Step4: Solve the equation for \(x\)

Subtract 3 from both sides of the equation \(x+3=12\):

$$x=12 - 3$$

$$x = 9$$

Answer:

9