Question

a pea plant that has round seeds has the genotype rr. it is crossed with a pea plant that has wrinkled seeds and the genotype rr. what is the probability that the offspring will have wrinkled seeds?
○ 0 percent
○ 25 percent
○ 50 percent
○ 75 percent

Explanation:

Step1: Determine the gametes

The plant with genotype \( Rr \) can produce two types of gametes: \( R \) and \( r \) (each with equal probability). The plant with genotype \( rr \) can only produce \( r \) gametes.

Step2: Create a Punnett square

	\( R \)	\( r \)
\( r \)	\( Rr \)	\( rr \)

From the Punnett square, we see that out of 4 possible combinations, 2 are \( rr \) (which gives wrinkled seeds) and 2 are \( Rr \) (which gives round seeds).

Step3: Calculate the probability

The probability of getting \( rr \) (wrinkled seeds) is \( \frac{2}{4} = 0.5 \) or 50 percent.

Answer:

50 percent (corresponding to the option "50 percent")