Question

part c
the momentum of an object is determined to be 7.2×10⁻³ kg·m/s. express this quantity as provided or use any equivalent unit. (note: 1 kg = 1000 g)

Explanation:

Step1: Convert kg to g

Since \(1\space kg = 1000\space g=10^{3}\space g\), we can rewrite the momentum \(p = 7.2\times 10^{-3}\space kg\cdot m/s\). Substitute \(kg\) with \(10^{3}\space g\):
\(p=7.2\times 10^{-3}\times10^{3}\space g\cdot m/s\)
Using the rule of exponents \(a^{m}\times a^{n}=a^{m + n}\), where \(a = 10\), \(m=-3\) and \(n = 3\), we have \(10^{-3}\times10^{3}=10^{-3 + 3}=10^{0}=1\)

Answer:

\(7.2\space g\cdot m/s\)