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Question
part 3 of 5
(d) express the equation needed for derivation in terms of \\(x\\): \\(a(x) = \frac{740x - 8x^2}{3}\\)
(e) \\(a(x) = \frac{740 - 16x}{3}\\)
part 4 of 5
(f) the critical value(s) in the domain is \\(46.25\\)
(g) use the second derivative test to ensure the critical value gives a maximum value for the area
\\(a(x) = -\frac{16}{3}\\) and \\(a(cv) = -\frac{16}{3}\\)
since \\(a(cv)\\) is negative, the critical value is at a maximum
continue to the next part.
part 5 of 5
(h) by the select an answer, the maximum area will have an \\(x\\) dimension of feet by a \\(y\\) dimension of feet using 370 feet of fencing material.
Identify the optimization context
Using the Optimization Problems and Domain of Optimization knowledge points
Determine the applicable theorem
Using the Optimization Problems knowledge point
Calculate the optimal dimensions
Using the Critical Points and Optimization Problems knowledge points
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By the Extreme Value Theorem, the maximum area will have an \(x\) dimension of 46.25 feet by a \(y\) dimension of 61.67 feet using 370 feet of fencing material.