Question

part a
consider pea plants with the genotypes ggtt and ggtt. these plants can each produce how many type(s) of gametes?
view available hint(s)
○ two... one
○ four... two
○ one... two
○ one... one
○ four... one

Explanation:

Step1: Analyze GgTt gametes

For a genotype with two heterozygous pairs (GgTt), we use the law of independent assortment. The number of gamete types is calculated as \(2^n\), where \(n\) is the number of heterozygous gene pairs. Here, \(n = 2\) (Gg and Tt), so \(2^2=4\) gamete types (GT, Gt, gT, gt).

Step2: Analyze ggtt gametes

For a homozygous genotype (ggtt), all gene pairs are homozygous. So, there's only 1 type of gamete (gt), since both alleles for each gene are the same, so no variation in gamete formation.

Step3: Match with options

The first plant (GgTt) produces 4 gametes, the second (ggtt) produces 1 gamete. So the option is "four... one".

Answer:

four... one