Question

part 2: clementine left the house to go on a walk. she went 2 miles south in one hour, and then returned home again. what was her average velocity? how do you know?

Explanation:

Step1: Recall the formula for average velocity

Average velocity $v_{avg}=\frac{\Delta x}{t}$, where $\Delta x$ is the displacement and $t$ is the total time.

Step2: Determine the displacement

Clementine goes 2 miles south and then returns home. Displacement is the straight - line distance from the initial to the final position. Since she starts and ends at the same place, $\Delta x = 0$ miles.

Step3: Consider the total time

She spends some time going south and some time coming back. Let's assume the time to go south is $t_1 = 1$ hour and the time to come back is $t_2$ (also 1 hour if we assume the same speed on the return trip, but it doesn't matter for the final result). The total time $t=t_1 + t_2>0$.

Step4: Calculate the average velocity

Using the formula $v_{avg}=\frac{\Delta x}{t}$, and since $\Delta x = 0$ and $t>0$, we have $v_{avg}=\frac{0}{t}=0$ miles per hour.

Answer:

0 miles per hour