Question

1. in parallelogram efgh, what is the relationship between angle e and angle g?

( e^{circ}+g^{circ}=180^{circ} )
( e^{circ}-g^{circ}=180^{circ} )
( e^{circ}=g^{circ} )

Explanation:

Step1: Recall the property of parallelogram

In a parallelogram, adjacent angles are supplementary.

Step2: Identify the relationship between angle \(e\) and angle \(g\)

In parallelogram \(EFGH\), \(e\) and \(g\) are adjacent angles.
So, \(e^{\circ}+g^{\circ}=180^{\circ}\)

Answer:

$e^{\circ}+g^{\circ}=180^{\circ}$