Question

in order for the parallelogram to be a rhombus, x = ?. (3x - 11)° (x + 23)°

Explanation:

Step1: Recall rhombus property

In a rhombus, the diagonals bisect the angles. So, the two given angles are equal, i.e., $3x - 11=x + 23$.

Step2: Solve the equation for x

Subtract x from both sides: $3x - x-11=x - x + 23$, which simplifies to $2x-11 = 23$. Then add 11 to both sides: $2x-11 + 11=23 + 11$, getting $2x=34$. Divide both sides by 2: $\frac{2x}{2}=\frac{34}{2}$, so $x = 17$.

Answer:

$17$