Question

order of operations
ccss.math: 6.ee.a.2, 6.ee.a.2.c
order the expressions from least to greatest.
$3^2$ $2^3 - 2^1$ $2^1 + 3^1$

Explanation:

Step1: Calculate \(3^2\)

\(3^2 = 3\times3 = 9\)

Step2: Calculate \(2^3 - 2^1\)

First, \(2^3 = 2\times2\times2 = 8\) and \(2^1 = 2\). Then \(8 - 2 = 6\)

Step3: Calculate \(2^1 + 3^1\)

\(2^1 = 2\) and \(3^1 = 3\), so \(2 + 3 = 5\)

Step4: Order the results

We have \(5\) (from \(2^1 + 3^1\)), \(6\) (from \(2^3 - 2^1\)), and \(9\) (from \(3^2\)). So the order from least to greatest is \(2^1 + 3^1\), \(2^3 - 2^1\), \(3^2\)

Answer:

\(2^1 + 3^1\), \(2^3 - 2^1\), \(3^2\)