Question

of operations. check your sol
b) $-6 = -3(k - 4)$
d) $14 = 2(s + 5)$

Explanation:

Step1: Solve for $k$: Divide both sides by -3

$\frac{-6}{-3} = \frac{-3(k-4)}{-3}$
$2 = k - 4$

Step2: Isolate $k$: Add 4 to both sides

$2 + 4 = k - 4 + 4$
$6 = k$

Step3: Check solution for $k$

Substitute $k=6$ into $-6=-3(k-4)$:
$-6 = -3(6-4)$
$-6 = -3(2)$
$-6 = -6$ (Valid)

Step4: Solve for $s$: Divide both sides by 2

$\frac{14}{2} = \frac{2(s+5)}{2}$
$7 = s + 5$

Step5: Isolate $s$: Subtract 5 from both sides

$7 - 5 = s + 5 - 5$
$2 = s$

Step6: Check solution for $s$

Substitute $s=2$ into $14=2(s+5)$:
$14 = 2(2+5)$
$14 = 2(7)$
$14 = 14$ (Valid)

Answer:

For part b): $k=6$
For part d): $s=2$