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3. in one of gregor mendels first experiments, he crossed a purple - fl…

Question

  1. in one of gregor mendels first experiments, he crossed a purple - flowered pea plant (pp) with a white - flowered pea plant (pp). purple flowers white flowers genotype probability (%) phenotype probability (%) pp purple flowers pp white flowers pp

Explanation:

Step1: Fill in the Punnett square

The Punnett square has two rows (from the white - flowered plant with alleles \(p\) and \(p\)) and two columns (from the purple - flowered plant with alleles \(P\) and \(P\)).
The four cells of the Punnett square will be \(Pp\), \(Pp\), \(Pp\), \(Pp\).

Step2: Calculate genotype probabilities

There are 0 cells with \(PP\), 4 cells with \(Pp\), and 0 cells with \(pp\).
The probability of \(PP=\frac{0}{4} = 0\%\)
The probability of \(Pp=\frac{4}{4}=100\%\)
The probability of \(pp=\frac{0}{4} = 0\%\)

Step3: Calculate phenotype probabilities

Since \(P\) (purple) is dominant over \(p\) (white), and all genotypes are \(Pp\), the probability of purple flowers (phenotype) is \(\frac{4}{4}=100\%\) and the probability of white flowers (phenotype) is \(\frac{0}{4}=0\%\)

Answer:

Genotype Probability (\%):

  • \(PP: 0\%\)
  • \(Pp: 100\%\)
  • \(pp: 0\%\)

Phenotype Probability (\%):

  • Purple Flowers: \(100\%\)
  • White Flowers: \(0\%\)