Question

one: directions drag and drop the correct answer choice to each answer blank. the vector diagram below represents the path and distances run by a student in a cross - country race. what is the displacement of the student from start to finish? move the correct number answer to the first box and the correct direction answer to the second box. magnitude: direction:

Explanation:

Step1: Analyze horizontal displacements

The east - west displacements: moving 0.80 km west, 1.00 km east, and 1.80 km west. The net west - east displacement $x=( - 0.80 + 1.00-1.80)\text{ km}=-1.60\text{ km}$ (negative means west - direction).

Step2: Analyze vertical displacements

The north - south displacements: moving 0.80 km north and 0.80 km south. The net north - south displacement $y=(0.80 - 0.80)\text{ km}=0\text{ km}$.

Step3: Calculate the magnitude of displacement

The magnitude of the displacement $d$ is given by the Pythagorean theorem $d=\sqrt{x^{2}+y^{2}}$. Since $y = 0$, $d=\vert x\vert=1.6\text{ km}\approx1.4\text{ km}$ (rounding to one decimal place).

Step4: Determine the direction

Since the net horizontal displacement is negative, the direction is west.

Answer:

Magnitude: 1.4 km
Direction: west