Question

one character in peas that mendel studied was yellow versus green seeds. a cross between a homozygous yellow line (yy) and a homozygous green line (yy) will result in f₁ plants that are heterozygous (yy) for this trait and produce yellow seeds.
when an f₁ plant undergoes meiosis, what gamete types will it produce, and in what proportions?
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Explanation:

Step1: Determine the genotype of F1

The parental cross is \( YY\times yy\). Using the Punnett - square or the principle of segregation, the \( F_{1}\) generation has the genotype \( Yy\).

Step2: Analyze gamete formation

According to Mendel's law of segregation, during meiosis, the two alleles of a gene separate. For a plant with genotype \( Yy\), the possible gametes are \( Y\) and \( y\).
The probability of getting a \( Y\) gamete: Since there are two alleles (\( Y\) and \( y\)) and they separate independently, the proportion of \( Y\) gametes is \(\frac{1}{2}\).
The probability of getting a \( y\) gamete: Similarly, the proportion of \( y\) gametes is \(\frac{1}{2}\).

Answer:

\(\frac{1}{2}Y\) and \(\frac{1}{2}y\)