Question

olynomials by mon... -9g(-2g + g²) + 3(g³ + 4)

Explanation:

Step1: Distribute -9g to the terms inside the first parentheses

$-9g(-2g) + (-9g)(g^2) + 3(g^3 + 4)$
$= 18g^2 - 9g^3 + 3(g^3 + 4)$

Step2: Distribute 3 to the terms inside the second parentheses

$18g^2 - 9g^3 + 3g^3 + 3\times4$
$= 18g^2 - 9g^3 + 3g^3 + 12$

Step3: Combine like terms (the $g^3$ terms)

$18g^2 + (-9g^3 + 3g^3) + 12$
$= 18g^2 - 6g^3 + 12$

Step4: Rearrange terms in standard form

$-6g^3 + 18g^2 + 12$

Answer:

$-6g^3 + 18g^2 + 12$