Question

1. is the object’s motion constant? explain.

its only constant once it hits 6m at 4s

1. what is the velocity during the first 4 seconds?

1.5 m/s

1. what is the velocity during the last 6 seconds?

drawing position - time graphs
problem 1: a car travels 6 meters in 3 seconds. it then stops for 5 seconds. then the car goes 2 meters in 2 seconds.
a. what is the velocity of the car for the first 3 seconds?
b. what is the velocity of the car from times 3 - 8 seconds?
c. during which time is the car moving faster, 0 - 3s or 8 - 10s? how could you know this without calculating the velocity?
problem 2: a car travels 8 meters in 2 seconds. it stays motionless for 3 seconds. it then goes - 5 meters in 5 seconds.
a. what is the velocity of the car for the first 2 seconds?
b. what is the velocity of the car from times 2 - 5 seconds?
c. what is the velocity of the car from times 5 - 10s?
problem 3: a car travels 5 meters in 2 seconds. the car then stays motionless for 2 seconds. it then moves 5 meters in the opposite direction in 4 seconds. last, the car moves forward at 3m/s for 2 seconds.
a. what is the velocity of the car for the first 2 seconds?
b. what is the velocity of the car from times 4 - 8 seconds?
c. how far did the car move from 8 - 10s?

Explanation:

Problem 1a:

Step1: Recall velocity formula

Velocity \( v = \frac{\Delta x}{\Delta t} \), where \( \Delta x \) is displacement, \( \Delta t \) is time.

Step2: Substitute values

\( \Delta x = 6 \, \text{m} \), \( \Delta t = 3 \, \text{s} \), so \( v = \frac{6}{3} = 2 \, \text{m/s} \).

Step1: Analyze motion (3 - 8 s)

The car stops, so displacement \( \Delta x = 0 \).

Step2: Calculate velocity

\( v = \frac{0}{5} = 0 \, \text{m/s} \) (time interval 8 - 3 = 5 s).

Step1: Compare slopes (0 - 3s vs 8 - 10s)

Slope of position - time graph is velocity. 0 - 3s slope: \( \frac{6}{3}=2 \); 8 - 10s: \( \frac{2}{2}=1 \). Steeper slope (0 - 3s) means faster.

Step2: Conclusion

0 - 3s is faster (steeper slope on graph).

Answer:

\( 2 \, \text{m/s} \)

Problem 1b: