Question

an object is dropped from the top of a tower with a height of 1190 feet. neglecting air resistance, the height of the object at time t seconds is given by the polynomial - 16t² + 1190. find the height of the object at t = 1 second. the height of the object at 1 second is □ feet.

Explanation:

Step1: Substitute \(t = 1\) into the height formula

The height formula is \(h(t)=-16t^{2}+1190\). When \(t = 1\), we have \(h(1)=-16\times(1)^{2}+1190\).

Step2: Calculate the value

First, calculate \(-16\times(1)^{2}=-16\times1=-16\). Then, \(h(1)=-16 + 1190\). Using the addition operation \(a+b\) where \(a=-16\) and \(b = 1190\), we get \(h(1)=1174\).

Answer:

\(1174\)