Question

an object has an acceleration of 6.0 m/s/s. if the net force acting upon this object were doubled, then its new acceleration would be ______ m/s/s.

Explanation:

Step1: Use Newton's second law

Newton's second law is \(F = ma\), where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration. Initially, \(F_1=m\times a_1\), and \(a_1 = 6.0\ m/s^2\).

Step2: Analyze the situation when force is doubled

When the force is doubled (\(F_2 = 2F_1\)), since mass \(m\) remains constant (assuming the object's mass doesn't change), from \(F_2=m\times a_2\) and \(F_2 = 2F_1\), \(F_1=m\times a_1\), we substitute \(F_1\) into \(F_2\) equation: \(2\times(m\times a_1)=m\times a_2\). Canceling out the mass \(m\) (because \(m
eq0\)) on both sides of the equation \(2a_1=a_2\).

Step3: Calculate the new acceleration

Substitute \(a_1 = 6.0\ m/s^2\) into \(a_2 = 2a_1\). So \(a_2=2\times6.0\ m/s^2\).

Answer:

\(12.0\)