Question

an object has an acceleration of 6.0 m/s/s. if the net force acting upon this object were doubled, then its new acceleration would be ______ m/s/s.

Explanation:

Step1: Use Newton's second law

Newton's second law is \(F = ma\), where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration. Initially, we have \(F_1=m\times a_1\), and \(a_1 = 6.0\space m/s^2\).

Step2: Analyze the new - force situation

If the net force is doubled (\(F_2 = 2F_1\)), and the mass \(m\) remains constant (since the object is the same). From \(F_2=m\times a_2\), substituting \(F_2 = 2F_1\) and \(F_1=m\times a_1\) into \(F_2=m\times a_2\), we get \(2F_1=m\times a_2\). Since \(F_1=m\times a_1\), then \(2(m\times a_1)=m\times a_2\).

Step3: Solve for the new acceleration

Cancel out the mass \(m\) (because \(m
eq0\)) from both sides of the equation \(2(m\times a_1)=m\times a_2\). We get \(a_2 = 2a_1\).

Answer:

\(12\)