Question

the number of swings back and forth of a pendulum of length l, in inches, each minute is $\frac{715}{sqrt{l}}$. how many more swings can pendulum 1 make than pendulum 2 each minute? round to the nearest whole number. pendulum 1 can make about more swings each minute

Explanation:

Step1: Calculate swings of Pendulum 1

For Pendulum 1 with $L_1 = 36$ inches, the number of swings $n_1=\frac{715}{\sqrt{36}}=\frac{715}{6}\approx119.17$.

Step2: Calculate swings of Pendulum 2

For Pendulum 2 with $L_2 = 48$ inches, the number of swings $n_2=\frac{715}{\sqrt{48}}=\frac{715}{4\sqrt{3}}\approx\frac{715}{4\times1.732}\approx103.07$.

Step3: Find the difference

The difference in the number of swings $\Delta n=n_1 - n_2\approx119.17- 103.07 = 16.1\approx16$.

Answer:

16