Question

this number line is broken into parts of equal size. what is true of the location of \\(\frac{2}{4}\\) on the number line?
a the distance between 0 and \\(\frac{2}{4}\\) is 2.
b both 0 and 1 are the same distance from \\(\frac{2}{4}\\).
c \\(\frac{2}{4}\\) is closer to 0 than 1 on the number line.
d \\(\frac{2}{4}\\) is twice as far from zero than it is from 1.

Explanation:

Step1: Analyze Option A

The distance between 0 and $\frac{2}{4}$ is calculated as $\vert \frac{2}{4}-0\vert=\frac{2}{4}=\frac{1}{2}$, not 2. So A is wrong.

Step2: Analyze Option B

Distance from 0 to $\frac{2}{4}$: $\vert \frac{2}{4}-0\vert=\frac{2}{4}=\frac{1}{2}$. Distance from 1 to $\frac{2}{4}$: $\vert 1 - \frac{2}{4}\vert=\vert\frac{4 - 2}{4}\vert=\frac{2}{4}=\frac{1}{2}$. So both distances are equal.

Step3: Analyze Option C

Distance from 0 to $\frac{2}{4}$ is $\frac{1}{2}$, distance from 1 to $\frac{2}{4}$ is also $\frac{1}{2}$, so it's equidistant, not closer to 0. C is wrong.

Step4: Analyze Option D

Since distance from 0 and 1 to $\frac{2}{4}$ is same, it's not twice as far from 0 than 1. D is wrong.

Answer:

B. Both 0 and 1 are the same distance from $\frac{2}{4}$.