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Question
now, find the exact length of the hypotenuse, c. thats the length of the line segment between point a and point b. use square root notation to write the exact value of c. you can solve below or solve on paper and then enter your answer on zearn.
a (8, 3)
$a^2 + b^2 = c^2$
$8^2 + 10^2 = c^2$
$c = \square$
b (-2, -5)
c (8, -5)
Step1: Calculate \(8^2 + 10^2\)
First, find the values of \(8^2\) and \(10^2\). \(8^2 = 64\) and \(10^2 = 100\). Then add them together: \(64 + 100 = 164\). So, \(c^2 = 164\).
Step2: Solve for \(c\)
To find \(c\), take the square root of both sides. Since \(c\) represents a length, we take the positive square root. So, \(c = \sqrt{164}\). We can simplify \(\sqrt{164}\) by factoring 164: \(164 = 4 \times 41\), so \(\sqrt{164} = \sqrt{4 \times 41} = \sqrt{4} \times \sqrt{41} = 2\sqrt{41}\). Wait, but wait, let's check the coordinates again. Wait, the horizontal distance between B(-2, -5) and C(8, -5) is \(8 - (-2) = 10\), and the vertical distance between A(8, 3) and C(8, -5) is \(3 - (-5) = 8\). So the legs are 10 and 8, so \(a = 8\), \(b = 10\). Then \(a^2 + b^2 = 64 + 100 = 164\), so \(c = \sqrt{164}\)? Wait, no, wait, 8 squared is 64, 10 squared is 100, sum is 164. But maybe I made a mistake in the vertical distance? Wait, point A is (8, 3), point C is (8, -5). So the vertical distance is \(3 - (-5) = 8\), correct. Horizontal distance between B(-2, -5) and C(8, -5) is \(8 - (-2) = 10\), correct. So then \(c^2 = 8^2 + 10^2 = 64 + 100 = 164\), so \(c = \sqrt{164}\). But \(\sqrt{164}\) can be simplified as \(2\sqrt{41}\), but maybe the problem expects the simplified radical form or the square root of 164. Wait, let's check again. Wait, 8 and 10: 8-10-? Wait, no, 8 and 10, so the hypotenuse is \(\sqrt{8^2 + 10^2} = \sqrt{64 + 100} = \sqrt{164} = 2\sqrt{41}\). But maybe the problem has a typo? Wait, no, looking at the graph, the horizontal segment is from x=-2 to x=8, so length 10, vertical segment from y=-5 to y=3, so length 8. So yes, 8 and 10. So \(c = \sqrt{8^2 + 10^2} = \sqrt{64 + 100} = \sqrt{164} = 2\sqrt{41}\). But let's compute \(\sqrt{164}\) numerically? Wait, no, the problem says "exact length", so we need to write it in square root notation. Wait, but 164 factors into 441, so \(\sqrt{164} = \sqrt{4*41} = 2\sqrt{41}\). Alternatively, maybe I messed up the legs. Wait, maybe the legs are 10 and 8, so the hypotenuse is \(\sqrt{10^2 + 8^2} = \sqrt{164}\). So the exact value is \(\sqrt{164}\) or \(2\sqrt{41}\). Let's check 164: 441, so yes, simplified is \(2\sqrt{41}\). But let's see, 8 squared is 64, 10 squared is 100, sum is 164. So \(c = \sqrt{164} = 2\sqrt{41}\). Wait, but maybe the problem has a mistake? Wait, no, the coordinates: B(-2, -5), C(8, -5), so horizontal distance 10, A(8, 3), C(8, -5), vertical distance 8. So the right triangle has legs 10 and 8, so hypotenuse is \(\sqrt{10^2 + 8^2} = \sqrt{164}\). So the exact length is \(\sqrt{164}\) or simplified as \(2\sqrt{41}\). Let's confirm: \(2\sqrt{41}\) squared is \(4*41 = 164\), which matches. So the exact length is \(\sqrt{164}\) or \(2\sqrt{41}\). But maybe the problem expects \(\sqrt{164}\) or simplified. Let's see, 164 is 4*41, so simplified is \(2\sqrt{41}\). So the answer is \(\sqrt{164}\) or \(2\sqrt{41}\). Wait, but let's check the calculation again. 8 squared is 64, 10 squared is 100, sum is 164. So \(c = \sqrt{164}\). Alternatively, maybe I made a mistake in the legs. Wait, maybe the vertical leg is 8, horizontal leg is 10, so the hypotenuse is \(\sqrt{8^2 + 10^2} = \sqrt{164}\). So the exact value is \(\sqrt{164}\), which can be simplified to \(2\sqrt{41}\). So the answer is \(\sqrt{164}\) or \(2\sqrt{41}\). Let's check with a calculator: \(\sqrt{164} \approx 12.806\), and \(2\sqrt{41} \approx 2*6.403 = 12.806\), so that's correct. So the exact length is \(\sqrt{164}\) (or \(2\sqrt{41}\)).
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\(\sqrt{164}\) (or \(2\sqrt{41}\))