Question

name

1. $\frac{620}{+921}$

2 round 0.358 to the underlined place.

1. $10×14=$
2. how much money is 8 quarters, 4 dimes, and 6 nickels?
3. $\frac{752,653}{-716,228}$
4. write the missing family fact.

$6×9 = 54$
$9×6 = 54$
$54÷9 = 6$

1. $19l=$ _ ml
2. is 37 a prime number or a composite number?
3. $39÷3=$
4. circle the name of the triangle:

isosceles equilateral scalene right

Explanation:

Step1: Add 620 and 921

$$\begin{align*} 620+921&=(600 + 20)+(900+21)\\ &=(600+900)+(20 + 21)\\ &=1500+41\\ &=1561 \end{align*}$$

Step2: Round 0.358 (assuming underlined digit is 5, tenths place not clear. If underlined is 3 (tenths), 0.4; if 5 (hundredths), 0.36. But common is 0.4 if tenths underlined)

If we assume rounding to tenths place:
Since the digit in the hundredths place is 5, we round up. So \(0.358\approx0.4\)

Step3: Calculate \(10\times14\)

Using the property of multiplication by 10: \(10\times14 = 140\)

Step4: Calculate the money

A quarter is $0.25$, a dime is $0.10$, a nickel is $0.05$

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Step5: Subtract 716228 from 752653

$$\begin{align*} 752653-716228&=(752653-700000)-(16228)\\ &=52653-16228\\ &=36425 \end{align*}$$

Step6: Find the missing family fact

Since \(6\times9 = 54\), \(9\times6=54\), \(54\div9 = 6\), then \(54\div6=9\)

Step7: Convert liters to milliliters

Since \(1L = 1000mL\), then \(19L=19\times1000 = 19000mL\)

Step8: Determine prime or composite

A prime number has only two distinct positive divisors: 1 and itself. For 37, the divisors are 1 and 37. So 37 is a prime number.

Step9: Calculate \(39\div3\)

\(39\div3=\frac{30 + 9}{3}=\frac{30}{3}+\frac{9}{3}=10 + 3=13\)

Step10: Identify the triangle

An equilateral triangle has all sides equal. From the figure (assuming equal - sided), circle equilateral.

Answer:

1. \(1561\)
2. \(0.4\) (assuming tenths place underlined)
3. \(140\)
4. \(\$2.70\)
5. \(36425\)
6. \(54\div6 = 9\)
7. \(19000\)
8. Prime number
9. \(13\)
10. Equilateral