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name: period: 1.f = 2.m = 3.a = 4.v = 5.d = 6.p = 125 kilograms 23 kgm/…

Question

name:
period:
1.f =
2.m =
3.a =
4.v =
5.d =
6.p =
125 kilograms
23 kgm/s
3 m/s²
29 meters/sec
228 meters
6 newtons

Explanation:

Step1: Recall force formula

The formula for force is $F = ma$.

Step2: Identify mass

Mass ($m$) is the amount of matter in an object, and its unit here is kilograms. So $m = 125$ kilograms.

Step3: Identify acceleration

Acceleration ($a$) is the rate of change of velocity. Its unit here is $m/s^{2}$, so $a=3\ m/s^{2}$.

Step4: Identify velocity

Velocity ($v$) is the rate of change of displacement. Its unit here is meters/sec, so $v = 29$ meters/sec.

Step5: Identify displacement

Displacement ($D$) is a vector - quantity representing the change in position. Its unit here is meters, so $D = 228$ meters.

Step6: Recall momentum formula

Momentum ($p$) is given by $p=mv$. But if we just consider the concept - wise filling, and from the given values and common physics quantities, momentum has units of $kg\cdot m/s$. Here we have a value with units $kg\cdot m/s$ which is $23\ kg\cdot m/s$, so $p = 23\ kg\cdot m/s$.

Answer:

  1. $ma$
  2. mass (125 kilograms)
  3. acceleration ($3\ m/s^{2}$)
  4. velocity (29 meters/sec)
  5. displacement (228 meters)
  6. momentum (23 kg·m/s)