QUESTION IMAGE
Question
name:
math 7
directions: answer each of the following questions. show all work.
- the length of a garden is represented by 4x. the width of the garden is represented by 5y. express the perimeter of the garden as a simplified expression.
- translate: the product of 6 and 21 minus a number
- solve: \\( \frac { 3 } { 5 } x = - 6 \\)
- solve: \\( 124 = - 11 x + 3 \\)
- simplify: \\( - 5 ( 1 + 2 k ) - 8 ( - 4 + 5 k ) \\)
- factor: \\( 80 x y - 16 x \\)
- translate: five more than twice a number
- use your expression from #7 to evaluate for when \\( m = 2.3 \\)
- compare the following: \\( - 1 \frac { 1 } { 2 } \textcircled { > } - 2 \\)
- evaluate:
a. \\( \sqrt { 49 } = \\)
b. \\( \sqrt { 8 } = \\)
c. \\( \sqrt { 100 } = \\)
teacher use only:
1. Perimeter of a rectangle formula
The formula for the perimeter \(P\) of a rectangle is \(P = 2(l + w)\), where \(l\) is the length and \(w\) is the width. Given \(l = 4x\) and \(w = 5y\).
2. Translating the phrase
“The product of 6 and 21” is \(6\times21\), and “minus a number” (let the number be \(n\)) gives \(6\times21 - n=126 - n\).
3. Solving the equation \(\frac{3}{5}x=-6\)
Multiply both sides of the equation by \(\frac{5}{3}\) to isolate \(x\).
4. Solving the equation \(124=-11x + 3\)
First, subtract 3 from both sides: \(124 - 3=-11x\), so \(121=-11x\). Then divide both sides by \(-11\).
5. Simplifying \(-5(1 + 2k)-8(-4 + 5k)\)
Use the distributive property \(a(b + c)=ab+ac\).
6. Factoring \(80xy-16x\)
Find the greatest common factor (GCF) of \(80xy\) and \(16x\). The GCF of 80 and 16 is 16, and the common variable factor is \(x\).
7. Translating “Five more than twice a number”
Let the number be \(m\). “Twice a number” is \(2m\), and “five more than” gives \(2m+5\).
9. Comparing \(-1\frac{1}{2}\) and \(-2\)
Convert \(-1\frac{1}{2}=-\frac{3}{2}=-1.5\). Since \(-1.5>-2\), we have \(-1\frac{1}{2}>-2\).
10. Evaluating square - roots
- For \(a.\), since \(7\times7 = 49\), \(\sqrt{49}=7\).
- For \(b.\), \(\sqrt{8}=\sqrt{4\times2}=2\sqrt{2}\approx2.83\).
- For \(c.\), since \(10\times10 = 100\), \(\sqrt{100}=10\).
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- \(8x + 10y\)
- \(126 - n\)
- \(x=-10\)
- \(x = - 11\)
- \(-50k + 27\)
- \(16x(5y - 1)\)
- \(2m + 5\)
- \(-1\frac{1}{2}>-2\)
10.
- a. \(7\)
- b. \(2\sqrt{2}\approx2.83\)
- c. \(10\)