name
dihybrid genetic crosses – chickens!
trait dominant allele recessive allele
feather color white (w) speckled (w)
number of toes five (f) three (f)
comb color hot pink (p) baby blue (p)
sound it makes cluck (c) woof (c)
1. suppose you have a homozygous white, five - toed rooster (wwff) and you cross it with a heterozygous white, three - toed hen (wwff). answer the following questions about this cross.
a. list the possible gamete combinations for the rooster:
b. list the possible gamete combinations for the hen:
c. perform the following dihybrid cross:
(a table is here)
d. what are all of the possible genotypes of the offspring?
e. what are all of the possible phenotypes of the offspring, and in what ratio?
2. suppose you cross a rooster that has a baby blue comb and is heterozygous for a cluck with a hen who is heterozygous for a hot pink comb and makes a “woof” sound.
a. what is the genotype for the rooster?
b. what is the genotype for the hen?

Question

name
dihybrid genetic crosses – chickens!
trait	dominant allele	recessive allele
feather color	white (w)	speckled (w)
number of toes	five (f)	three (f)
comb color	hot pink (p)	baby blue (p)
sound it makes	cluck (c)	woof (c)
1. suppose you have a homozygous white, five - toed rooster (wwff) and you cross it with a heterozygous white, three - toed hen (wwff). answer the following questions about this cross.
   a. list the possible gamete combinations for the rooster:
   b. list the possible gamete combinations for the hen:
   c. perform the following dihybrid cross:
   (a table is here)
   d. what are all of the possible genotypes of the offspring?
   e. what are all of the possible phenotypes of the offspring, and in what ratio?
2. suppose you cross a rooster that has a baby blue comb and is heterozygous for a cluck with a hen who is heterozygous for a hot pink comb and makes a “woof” sound.
   a. what is the genotype for the rooster?
   b. what is the genotype for the hen?

Accepted Answer

# 1.
## a.
# Brief Explanations:
The rooster is homozygous $WWFF$. For gamete formation, each gamete gets one allele from each gene pair. Since it is homozygous for both traits ($WW$ and $FF$), using the principle of segregation (each gamete gets one allele of each gene), the only possible combination is $WF$.
# Answer:
$WF$

## b.
# Brief Explanations:
The hen is heterozygous for feather - color ($Ww$) and homozygous recessive for toe - number ($ff$). Using the principle of segregation, for the $Ww$ gene pair, it can contribute $W$ or $w$, and for the $ff$ gene pair, it can only contribute $f$.
# Answer:
$Wf$ and $wf$

## c.
# Brief Explanations:
Set up a Punnett square. The rooster has only one type of gamete ($WF$), and the hen has two types ($Wf$ and $wf$).
# Answer:
| | $Wf$ | $wf$ |
|---|---|---|
| $WF$ | $WWFf$ | $WwFf$ |

## d.
# Brief Explanations:
From the Punnett square in part c, we can directly read the genotypes.
# Answer:
$WWFf$ and $WwFf$

## e.
# Brief Explanations:
For $WWFf$ and $WwFf$, since $W$ (white) is dominant over $w$ (speckled) and $F$ (five - toed) is dominant over $f$ (three - toed). All offspring will have white feathers ($W$ is present in both genotypes) and five toes ($F$ is present in both genotypes).
# Answer:
All offspring will have white feathers and five toes (ratio $1:0$ for white : speckled and $1:0$ for five - toed : three - toed)

# 2.
## a.
# Brief Explanations:
The rooster has a baby - blue comb ($p$ is recessive for baby - blue, so $pp$) and is heterozygous for cluck ($C$ is dominant for cluck, so $Cc$).
# Answer:
$ppCc$

## b.
# Brief Explanations:
The hen is heterozygous for a hot - pink comb ($P$ is dominant for hot - pink, so $Pp$) and makes a “woof” sound ($e$ is recessive for woof, so $ee$).
# Answer:
$Ppee$

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