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name date go each arc is shown in blue. each indicated angle is the cen…

Question

name date
go
each arc is shown in blue. each indicated angle is the central angle that intercepts the given arc.

  1. given: ( r = 4 ) inches and ( overline{ab}=\frac{8pi}{3} ) inches 18. given: ( r = 18 mathrm{~cm} ) and ( overline{ge}=21pi mathrm{~cm} )

find ( mangle bca ) in radians. find ( mangle gfe ) in radians.

  1. given: ( r = 10 mathrm{~m} ) and ( overline{nl}=\frac{15pi}{2} mathrm{~m} ) 19. given: ( r = 27 mathrm{yd} ) and ( overline{pq}=3pi mathrm{yd} )

find ( mangle lmn ) in radians. find ( mangle prq ) in radians.

  1. each radius and arc length includes a unit such as feet or meters. explain why radian measures do not include a unit.

Explanation:

Step1: Use the arc - length formula

The formula for arc - length is \(s = r\theta\), where \(s\) is the arc - length, \(r\) is the radius, and \(\theta\) is the central angle in radians. So, \(\theta=\frac{s}{r}\)

Step2: Solve for \(\theta\) in each problem

  • Problem 16:

Given \(r = 4\) inches and \(s=\widehat{AB}=\frac{8\pi}{3}\) inches.
Substitute into \(\theta=\frac{s}{r}\), we get \(\theta=\frac{\frac{8\pi}{3}}{4}=\frac{2\pi}{3}\) radians.

  • Problem 17:

Given \(r = 10\) m and \(s=\widehat{NL}=\frac{15\pi}{2}\) m.
Substitute into \(\theta=\frac{s}{r}\), we get \(\theta=\frac{\frac{15\pi}{2}}{10}=\frac{3\pi}{4}\) radians.

  • Problem 18:

Given \(r = 18\) cm and \(s=\widehat{GE}=21\pi\) cm.
Substitute into \(\theta=\frac{s}{r}\), we get \(\theta=\frac{21\pi}{18}=\frac{7\pi}{6}\) radians.

  • Problem 19:

Given \(r = 27\) yd and \(s=\widehat{PQ}=3\pi\) yd.
Substitute into \(\theta=\frac{s}{r}\), we get \(\theta=\frac{3\pi}{27}=\frac{\pi}{9}\) radians.

Step3: Explain why radian measures have no unit

Radian is defined as the ratio of the arc - length \(s\) to the radius \(r\) (\(\theta=\frac{s}{r}\)). Since both \(s\) and \(r\) have the same unit (e.g., meters, inches, etc.), when we take the ratio \(\frac{s}{r}\), the units cancel out. For example, if \(s\) is in meters and \(r\) is in meters, \(\frac{\text{meters}}{\text{meters}} = 1\) (a dimensionless quantity)

Answer:

  1. \(\frac{2\pi}{3}\) radians
  2. \(\frac{3\pi}{4}\) radians
  3. \(\frac{7\pi}{6}\) radians
  4. \(\frac{\pi}{9}\) radians
  5. Radian is the ratio of arc - length to radius (\(\theta=\frac{s}{r}\)), and units of \(s\) and \(r\) cancel out.