Question

multiply. assume b is greater than or equal to zero, and write your answer in simplest form. (sqrt{5}cdotsqrt{98b^{4}})

Explanation:

Step1: Simplify $\sqrt{98b^{4}}$

We know that $98 = 49\times2$ and $b^{4}=(b^{2})^{2}$. So, $\sqrt{98b^{4}}=\sqrt{49\times2\times(b^{2})^{2}} = 7b^{2}\sqrt{2}$.

Step2: Multiply by $\sqrt{5}$

$\sqrt{5}\cdot\sqrt{98b^{4}}=\sqrt{5}\cdot7b^{2}\sqrt{2}=7b^{2}\sqrt{5\times2}=7b^{2}\sqrt{10}$

Answer:

$7b^{2}\sqrt{10}$