Question

multiple choice question
given that plancks constant is 6.6×10⁻³⁴ j·s, what is the energy of a photon of light with a frequency of 1.1×10¹⁶ s⁻¹?
7.3×10⁻¹⁸ j
4.0×10⁻⁵¹ s⁻¹
1.7×10⁵¹ s⁻¹
6.0×10⁻⁵¹ s⁻¹

Explanation:

Step1: Recall the formula for photon energy

The energy of a photon is given by \(E = h
u\), where \(h\) is Planck's constant and \(
u\) is the frequency.

Step2: Substitute the given values

Given \(h = 6.6\times10^{-34}\text{ J·s}\) and \(
u=1.1\times 10^{16}\text{ s}^{-1}\), substitute into the formula:
\(E=(6.6\times 10^{-34})\times(1.1\times 10^{16})\)

Step3: Perform the multiplication

Using the rule \(a^m\times a^n=a^{m + n}\) for exponents and multiplying the coefficients:
\((6.6\times1.1)\times10^{-34 + 16}=7.26\times10^{-18}\text{ J}\approx7.3\times 10^{-18}\text{ J}\)

Answer:

\(7.3\times 10^{-18}\text{ J}\)