Question

7 multiple choice 1 point a student applies a force to a cart to pull it up an inclined plane at constant speed during a physics lab. a force of 20 n is applied parallel to the incline to lift a 3.00 - kg loaded cart to a height of 0.450 m along an incline which is 0.746 - m long. determine the work done upon the cart and the subsequent potential energy change of the cart 14.92 j 28.55 j 13.2 j 0 j

Explanation:

Step1: Calculate the work done

Work done \(W = F\times d\), where \(F = 20\space N\) and \(d=0.746\space m\)
\(W=20\times0.746 = 14.92\space J\)

Step2: Calculate the potential energy change

Potential energy change \(\Delta U=mgh\), where \(m = 3.00\space kg\), \(g = 9.8\space m/s^{2}\), \(h = 0.450\space m\)
\(\Delta U=3\times9.8\times0.450=13.23\approx13.2\space J\)

Answer:

Work done: \(14.92\space J\), Potential energy change: \(13.2\space J\)