Question

8 multiple answer 1 point determine which of the following equations have a solution of p = 4. $\frac{p}{3}+4 = 5$ $\frac{p}{2}=-2$ $2p + 2 = 10$ $12 = 3p$ $4p-5 = 11$

Explanation:

Step1: Check first equation

Substitute $p = 4$ into $\frac{p}{3}+4 = 5$. We get $\frac{4}{3}+4=\frac{4 + 12}{3}=\frac{16}{3}
eq5$.

Step2: Check second equation

Substitute $p = 4$ into $\frac{p}{2}=-2$. We get $\frac{4}{2}=2
eq - 2$.

Step3: Check third equation

Substitute $p = 4$ into $2p + 2=10$. We have $2\times4+2=8 + 2=10$.

Step4: Check fourth equation

Substitute $p = 4$ into $12 = 3p$. We get $3\times4=12$.

Step5: Check fifth equation

Substitute $p = 4$ into $4p-5 = 11$. We have $4\times4-5=16 - 5=11$.

Answer:

$2p + 2 = 10$, $12 = 3p$, $4p-5 = 11$