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Question
the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer. a 12-foot pole is supporting a tent and has a rope attached to the top. the rope is pulled straight and the other end is attached to a peg two foot above the ground. the rope and the pole form an angle that measures 40°, as shown below. image of a right triangle with 12 ft vertical side, 2 ft horizontal side from the peg, and the rope as the hypotenuse with a 40° angle between the pole and the rope which expression shows the length of the rope? options: \\(\frac{10}{\cos 40^{\circ}} + 2 \approx 15.1\\) feet, \\(\frac{10}{\cos 40^{\circ}} \approx 13.1\\) feet, \\(\frac{12}{\cos 40^{\circ}} - 2 \approx 13.7\\) feet, \\(\frac{12}{\cos 40^{\circ}} \approx 15.7\\) feet
Step1: Analyze the triangle
The pole is 12 ft, and the peg is 2 ft above the ground, so the vertical side adjacent to the 40° angle in the right triangle is \(12 - 2=10\) ft. Let the rope length be \(x\).
Step2: Use cosine function
In a right triangle, \(\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}\). Here, \(\theta = 40^\circ\), adjacent side is 10 ft, hypotenuse is \(x\) (rope length). So \(\cos40^\circ=\frac{10}{x}\), which rearranges to \(x = \frac{10}{\cos40^\circ}\).
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\(\boldsymbol{\frac{10}{\cos 40^{\circ}} \approx 13.1}\) feet (the option with this expression)