Question

module 4 review-transformations and symmetry
due tuesday by 11:59pm points 25 submitting an external tool available after c
question 2 q | module 4 review-transformations and symmetry
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when point f is reflected in y = x, the image is located at f(6, -9).
point f is located at ( , )

Explanation:

Step1: Recall the reflection rule over \(y = x\)

When a point \((a,b)\) is reflected over the line \(y=x\), the image is \((b,a)\).

Step2: Apply the rule to find the original point

If the image after reflection over \(y = x\) is \(F'(6,-9)\), then using the rule \((a,b)\to(b,a)\) in reverse. Let the original point \(F=(x,y)\). Since \(x=-9\) and \(y = 6\) (because if \((y,x)=(6,-9)\), then \(x=-9,y = 6\)).

Answer:

\((-9,6)\)