) this model represents the magnetic field between two bar magnets. the midpoint between the two magnets, a, is labeled.
what will happen if a magnetic paper clip were placed at point a? complete the sentences.
the paper clip is attracted to the south pole of the magnet on the left and ____ the north pole of the magnet on the right. these two mag attracted to ____. so, the paper clip will

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# Brief Explanations:
1. Recall the property of magnets: Opposite poles attract, like poles repel.
2. The left magnet has a south pole (S) near point A, and the right magnet has a north pole (N) near point A.
3. A magnetic paper clip (a ferromagnetic material) will be attracted to both opposite poles (S of left, N of right) because opposite poles attract.
4. For the second blank, since the left's S and right's N are opposite to the paper clip's induced poles (when placed in the field, the paper clip will have poles induced such that it's attracted to S and N), the force on the paper clip from the left S is attraction, and from the right N is also attraction. So the second blank should be "attracted to" (as the north pole of the right magnet is opposite to the induced south pole of the paper clip, leading to attraction).
5. These two attractive forces will act on the paper clip, and since both are attractive (towards left S and right N, but let's check the direction: left S is to the left of A, right N is to the right of A? Wait, no: left magnet's S is at the right end of left magnet, right magnet's N is at the left end of right magnet. So point A is between left S (right of left magnet) and right N (left of right magnet). So the left S is to the left of A? Wait, no: left magnet is N (left) - S (right), so S is on the right side of left magnet. Right magnet is N (left) - S (right), so N is on the left side of right magnet. So point A is between left S (right of left magnet) and right N (left of right magnet). So the distance from A to left S and A to right N: let's see the diagram. So the left S is at the right end of left magnet, right N is at the left end of right magnet. So A is between them. So the paper clip at A: the left S (south) will attract it (since opposite poles: paper clip will have a north pole induced near S, so S attracts N), and the right N (north) will attract it (paper clip will have a south pole induced near N, so N attracts S). Wait, but the question is about the force on the paper clip from the right magnet's north pole. So the paper clip (ferromagnetic) will be attracted to the north pole of the right magnet because the north pole of the magnet and the induced south pole of the paper clip attract. So the second blank: the paper clip is attracted to the south pole of left magnet and attracted to the north pole of right magnet. Then, these two attractive forces: since the left S is pulling it to the left, and the right N is pulling it to the right? Wait, no: left S is on the right of left magnet, so to the left of A? Wait, no, left magnet: N (left) --- S (right). So S is at the right end of left magnet. Right magnet: N (left) --- S (right). So N is at the left end of right magnet. So the distance from A to left S: A is between left S (right end of left magnet) and right N (left end of right magnet). So left S is to the left of A? No, left S is at the right end of left magnet, so if left magnet is on the left, its S is on the right, so A is to the right of left S? Wait, maybe I got the direction wrong. Let's look at the magnetic field lines: the field lines go from N to S. So left magnet: N (left) to S (right), so field lines go from N to S (left to right in left magnet). Right magnet: N (left) to S (right), so field lines go from N to S (left to right in right magnet). Between the two magnets: left magnet's S (right end) and right magnet's N (left end). So the field lines between them: from right magnet's N (left end) to left magnet's S (right end)? Wait, no: magnetic field lines go from North to South outside the magnet. So left magnet: N (left) is source, S (right) is sink. Right magnet: N (left) is source, S (right) is sink. So between left S (sink) and right N (source), the field lines go from right N (source) to left S (sink), so from right to left. So the magnetic field at A is directed from right N to left S (leftward). But the paper clip is a ferromagnetic material, so it will be magnetized by the field. The induced dipole in the paper clip: the field at A is leftward, so the paper clip will have a north pole on the left (opposite to field direction, since field is from N to S, so the induced north pole is where the field is entering? Wait, maybe simpler: opposite poles attract. So the left magnet's S (south) will attract the paper clip (which can be considered as having a north pole induced near S), and the right magnet's N (north) will attract the paper clip (which has a south pole induced near N). So both forces are attractive. Now, the second blank: the paper clip is attracted to the south pole of left magnet and attracted to the north pole of right magnet. Then, the two forces: since left S is to the left of A (wait, no, left S is at the right end of left magnet, so A is to the right of left S? Wait, the left magnet is on the left, with N (left) and S (right). So the S is at the rightmost part of left magnet. The right magnet is on the right, with N (left) and S (right). So N is at the leftmost part of right magnet. So A is between the right end of left magnet (S) and the left end of right magnet (N). So the distance from A to left S: A is to the right of left S? No, left S is at the right end of left magnet, so A is to the right of left S? Wait, the diagram shows the two magnets with S (right of left) and N (left of right), and A is between them. So left S is at x = L, right N is at x = R, A is at x = (L+R)/2. So the left S is at x = L, A is at x = (L+R)/2 > L, so A is to the right of left S. Right N is at x = R, A is at x = (L+R)/2 < R, so A is to the left of right N. So the left S (x = L) is to the left of A (x = (L+R)/2), and right N (x = R) is to the right of A. Wait, no: L is the right end of left magnet, R is the left end of right magnet. So L < R, A is between L and R. So left S is at L, right N is at R. So A is between L and R. So the left S is at L (left of A), right N is at R (right of A). So the paper clip at A: left S (south) is to the left of A, right N (north) is to the right of A. So the left S attracts it (towards L, left), and the right N attracts it (towards R, right). But since both are attractive, what's the net force? Wait, but the question is about the force from the right magnet's north pole: the paper clip is attracted to the north pole of the right magnet (because north and south attract: the paper clip, when near north pole, will have a south pole induced, so north attracts south). So the second blank should be "attracted to". Then, the two forces (attractive from left S and attractive from right N) will act on the paper clip. But let's check the options: the dropdown for the second blank has "attracted to" and "repelled by". Since the right magnet's north pole and the paper clip (ferromagnetic) will have opposite poles induced (paper clip's south pole near right N), so they attract. So the second blank is "attracted to". Then, the third part: "These two mag [attracted to] : [dropdown]". Wait, maybe the question is about the direction or the net effect, but the main point is that the paper clip is attracted to both the south pole of the left magnet and the north pole of the right magnet (since opposite poles attract in both cases: S attracts N (of paper clip), N attracts S (of paper clip)). So the second blank is "attracted to".
# Answer:
The second blank (for the north pole of the magnet on the right) should be filled with "attracted to". So the completed sentence: "The paper clip is attracted to the south pole of the magnet on the left and attracted to the north pole of the magnet on the right."

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